A(x+3)(x^2+3)=x^2+15

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Solution for A(x+3)(x^2+3)=x^2+15 equation: 



(A+3)(A^2+3)=A^2+15

We move all terms to the left:

(A+3)(A^2+3)-(A^2+15)=0

We get rid of parentheses

-A^2+(A+3)(A^2+3)-15=0

We add all the numbers together, and all the variables

-1A^2+(A+3)(A^2+3)-15=0

We move all terms containing A to the left, all other terms to the right

-1A^2+(A+3)(A^2+3)=15

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